If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3(4x^2-10x+4)=0
We multiply parentheses
12x^2-30x+12=0
a = 12; b = -30; c = +12;
Δ = b2-4ac
Δ = -302-4·12·12
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-18}{2*12}=\frac{12}{24} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+18}{2*12}=\frac{48}{24} =2 $
| 680*3=-120*2x | | 0=-16t^2-96t-10 | | 0=-3n-5n | | 1-9x=-2 | | 8(w-2)-5w=11 | | 23=5y+2(y+8) | | -9=1-k-5 | | 2x-21=3x-45 | | 2x/x+1=2x+1/x | | -6p+5+2p=9 | | 3v+2(v-6)=13 | | 10x+1650=21x | | -2=2u+8(u+6) | | 3n-10=24 | | -7=k-3-5 | | g-3/3=5-3 | | -4p-5p=0 | | 3(-3x-1)-9=-5(x-4) | | 15/48=x/15 | | 4(x-3)+8=9x-10 | | 13x-8x-12=13 | | -79x-40+5x=91 | | 6y-5=20-7y | | 5(7+5y)+5=140 | | 57(y−3)−397=−657(y−3)−397=−6 | | 9,63=5,73(1+0,32x) | | 3/4x-1/3=5/6 | | 5/6*c+3/4=11/12 | | 5.5x=52.25 | | 6a^2=-30a | | 12=3b+b | | -5v-5=5v |